Leetcode 4. Median of Two Sorted Arrays
2 min readAug 9, 2021
[hard]
Given two sorted arrays nums1
and nums2
of size m
and n
respectively, return the median of the two sorted arrays.
The overall run time complexity should be O(log (m+n))
.
Example 1:
Input: nums1 = [1,3], nums2 = [2]
Output: 2.00000
Explanation: merged array = [1,2,3] and median is 2.
Example 2:
Input: nums1 = [1,2], nums2 = [3,4]
Output: 2.50000
Explanation: merged array = [1,2,3,4] and median is (2 + 3) / 2 = 2.5.
Example 3:
Input: nums1 = [0,0], nums2 = [0,0]
Output: 0.00000
Example 4:
Input: nums1 = [], nums2 = [1]
Output: 1.00000
Example 5:
Input: nums1 = [2], nums2 = []
Output: 2.00000
Constraints:
nums1.length == m
nums2.length == n
0 <= m <= 1000
0 <= n <= 1000
1 <= m + n <= 2000
-106 <= nums1[i], nums2[i] <= 106
[Java]
This problem ask time complexity be O(log(m+n)), but the solution is hard to understand. I will post a O(m+n) solution. It’s worse than optimal solution, but easier to understand and discuss.
- know the total count for two arrays, and move from front to end until we meet the middle point.
- 4 kind of situations, end of the array still not meet the middle point(array 1 and array 2), array1 number smaller than array2, than move array1 number forwarder.
- if there is odd number, we can just return the number we stop; if there is even number, we should divid the number, and the answer need to change to float.